Assume:
β = 1.0
κ = 0.4
a = 2D50 = 0.0017 ft
Calculate:
V* = (g yoS)1/2 = [(32.2) (14.1) (0.00021)]1/2 = 0.309 ft/s
ω
0.1109
z=
=
= 0.898
βκV* (1.0) (0.4)(0.309)
Calculate the concentration versus distance profile given in Table 4.6:
Table 4.6. Concentration vs. Elevation Above the Bed.
y (ft)
C (mg/l)
0.3
7,300
1
2,360
2
1,180
4
538
8
183
10
105
12
49
14
3
4.13.3 Problem 2 Using the Meyer-Peter and Mller Equation Calculate the
Bed Sediment Discharge (Bed Load)
In this example problem the U.S. Bureau of Reclamation formulation of the equation
(Equation 4.19) will be used.
Given:
A rectangular channel and the following data:
=
1.9 mm
D50
D90
=
2.8 mm
=
1.41
G
n
=
0.04
nw
=
1.5 n = 0.06
=
9.8 ft
yo
Sf
=
0.0005 (ft/ft)
=
2.01 mm
Dm
W
=
200 ft
4.43
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