Assume:
β = 1.0
κ = 0.4
a = 2D50 = 0.00051 m
Calculate:
= (g yoS)1/2 = [(9.81) (4.30) (0.00021)]1/2 = 0.0941 m/s
V*
ω
0.0338
z=
=
= 0.898
βκV* (1.0) (0.4) (0.0941)
Calculate the concentration versus distance profile given in Table 4.5:
Table 4.5. Concentration vs. Elevation Above the Bed.
y (m)
C (mg/l)
0.091
7,230
0.305
2,370
0.61
1,160
1.22
531
2.44
181
3.05
104
3.66
48
4.27
3
4.12.3 Problem 2 Using the Meyer-Peter and Mller Equation
Calculate the Bed Sediment Discharge (Bed Load)
In this example problem the U.S. Bureau of Reclamation formulation of the equation
(Equation 4.19) will be used.
Given:
A rectangular channel and the following data:
=
1.9 mm
D50
=
2.8 mm
D90
=
1.41
G
n
=
0.04
=
1.5 n = 0.06
nw
=
2.99 m
yo
Sf
=
0.0005 m/m
=
2.01 mm
Dm
W
=
60.96 m
4.38
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